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Latent Heat of Vaporization Equation

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anubis512

Mechanical
Joined
Jul 29, 2013
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21
Location
US
Hi All,

I'm trying to calculate the latent heat of vaporization of a chemical using the equation found in Perry's Chemical Handbook, Table 2-150. It gives the latent heat equation and chemical specific constants. My issue is I can't get that equation, which outputs J/kmol, to convert correctly to BTU/lb. I tried using water as a test chemical to make sure I was using the equation correctly, and it won't work.

The table says the listed are "latent heat values at Tmin X 1E-07". For water, this comes out to (and is listed as)4.4733x10^-7 J/kmol at 0C.


Does anyone have experience with using this equation from Perry's or converting it to BTU/lb?



Thanks!
 
The tabulated value for water should be multiplied by 107 since it has been given as multiplied by 10-7. Therefore, the reading should be 4.4733[×]107 J/kmol.

To get J/g = kJ/kg, divide this value by 18,015 g/kmol.
The conversion from kJ/kg to Btu/lb is an easy operation.
 
You may use:
1 Btu/lb = 2.326 kJ/kg​
 
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