×
INTELLIGENT WORK FORUMS
FOR ENGINEERING PROFESSIONALS

Log In

Come Join Us!

Are you an
Engineering professional?
Join Eng-Tips Forums!
  • Talk With Other Members
  • Be Notified Of Responses
    To Your Posts
  • Keyword Search
  • One-Click Access To Your
    Favorite Forums
  • Automated Signatures
    On Your Posts
  • Best Of All, It's Free!

*Eng-Tips's functionality depends on members receiving e-mail. By joining you are opting in to receive e-mail.

Posting Guidelines

Promoting, selling, recruiting, coursework and thesis posting is forbidden.

Students Click Here

Pressure Change Due to Piping Length
3

Pressure Change Due to Piping Length

Pressure Change Due to Piping Length

(OP)
DILEMMA
Because the length of piping and no other variables are changing, I am looking for a basic formula for determining the additional pressure change, as it relates to additional pipe length.

BACKGROUND
I am doing a basic, dual-phase vacuum process.

There are times when the process is only removing ambient air and minor levels of vapors.  There are also times when the dual-phase is operating and water is also being removed.

I need to perform the same task, at an alternate location, on the site.  The only variable that is changing is the necessary length of the 1" ID plastic tubing.

Replies continue below

Recommended for you

RE: Pressure Change Due to Piping Length

2
Do you have Crane #410 (Flow of Fluids)?  Page 2-8 discusses how to figure pressure drop in straight runs of pipe..

Patricia Lougheed

RE: Pressure Change Due to Piping Length

(OP)
I do not have this document.

Is this publicly available or something that must be purchased?

RE: Pressure Change Due to Piping Length

You have to buy Crane - it's about $30 and can be ordered over the web at:  http://www.vervante.com/crane/ .  I highly recommend getting a copy of this if you're going to be doing any work with fluid flow.

I'll try to condense the basics here, but I need to warn you I may be leading you astray...I'm a nuclear engineer and picked up my fluid flow knowledge over the years.  Also I've only worked with water systems so don't know how two-phase flow affects the pressure drop and what limitations you have on it.

Basically the head loss (h) (or pressure drop) is a function of the (1) roughness of the pipe (f) , (2) length of pipe (L), (3) diameter of pipe (D) and (4) velocity of the fluid through the pipe (v).

formula is h=f*L/D*(v^2)/2g for non-compressible fluids

For compressible fluids (such as air and vapor), the formulae change with the amount of pressure drop expected.  If the pressure drop is fairly small (you're not adding a whole lot of piping), you can use the above formula.  If it's large, then the formulas get complicated.

If you're looking for more than a rough answer, it might be worthwhile to hire someone who knows about this.

Patricia Lougheed

Red Flag This Post

Please let us know here why this post is inappropriate. Reasons such as off-topic, duplicates, flames, illegal, vulgar, or students posting their homework.

Red Flag Submitted

Thank you for helping keep Eng-Tips Forums free from inappropriate posts.
The Eng-Tips staff will check this out and take appropriate action.

Reply To This Thread

Posting in the Eng-Tips forums is a member-only feature.

Click Here to join Eng-Tips and talk with other members! Already a Member? Login



News


Close Box

Join Eng-Tips® Today!

Join your peers on the Internet's largest technical engineering professional community.
It's easy to join and it's free.

Here's Why Members Love Eng-Tips Forums:

Register now while it's still free!

Already a member? Close this window and log in.

Join Us             Close