×
INTELLIGENT WORK FORUMS
FOR ENGINEERING PROFESSIONALS

Log In

Come Join Us!

Are you an
Engineering professional?
Join Eng-Tips Forums!
  • Talk With Other Members
  • Be Notified Of Responses
    To Your Posts
  • Keyword Search
  • One-Click Access To Your
    Favorite Forums
  • Automated Signatures
    On Your Posts
  • Best Of All, It's Free!

*Eng-Tips's functionality depends on members receiving e-mail. By joining you are opting in to receive e-mail.

Posting Guidelines

Promoting, selling, recruiting, coursework and thesis posting is forbidden.

Students Click Here

Quickfield vs Maxwell SV

Quickfield vs Maxwell SV

Quickfield vs Maxwell SV

(OP)
Hello everyone,

i am modeling a simple magnetic system with an U shaped yoke to pull an armature (see attached picture), i download quickfield and maxwell SV, i model the same geometry on both softwares, and i try to get the force exherted on the armature and i get different results, in quickfield i get a magnitude of .025N with an angle of 269 and with maxwell i get a magnitude of .039N with an angle of 270.5.
I already check and i have the same material properties and the same geometry dimensions and the same current density on the current carrying cable.

Am i missing something ? Boundary conditions maybe.

I know that quickfield calculate the integrals over 1 meter in the z direction, is the same thing for Maxwell SV ?
 
can this depth number be modified in Maxwell SV ?

If the software calculates 1N of force on the armature and is calculated over 1 meter in z direction it means if a wan to know the force if i had 50 cm depth in the z direction the force will be the half thats 1N/2= .5N ?

Any idea where i can find more info on understanding 2d FEA ?

Thanks in advanced ??

 
Replies continue below

Recommended for you

RE: Quickfield vs Maxwell SV

I use Quickfied.  You are right in that you have to multiply the force number it gives you (actually force/depth) by the actual depth of your device.  I would assume Maxwell (if it's a 2d program) would require a similar step.  

Try running a textbook (easy model and known answer) problem in each to figure out what is going on.

RE: Quickfield vs Maxwell SV

Do both solutions assume infinite length?  I would expect them to in a 2D solution but in the real world you will have fringing on each end.  One solution may try to approximate the fringing.  I don't use either program so I don't know any details on their solvers.

RE: Quickfield vs Maxwell SV

(OP)
On quickfield you can define the length, in this case is 1 meter, on maxwell i dont know , i am guessing that is also 1 meter .

but i have another question, how will fringing affect the force exherted over the armature ?

what i think is that fringing will reduce the efective magnetic field on the armature reducing also the force, is this correct ?

Thanks

RE: Quickfield vs Maxwell SV

Force calculations are notoriously finicky in FEM.  Make sure you have a very dense mesh before running this result then, to be sure, double the mesh and run it again comparing the results to the first time.  If the results are significantly different then your solution is not converged and your results are no good.  Keep bumping up mesh density until you get a converged solution.

Red Flag This Post

Please let us know here why this post is inappropriate. Reasons such as off-topic, duplicates, flames, illegal, vulgar, or students posting their homework.

Red Flag Submitted

Thank you for helping keep Eng-Tips Forums free from inappropriate posts.
The Eng-Tips staff will check this out and take appropriate action.

Reply To This Thread

Posting in the Eng-Tips forums is a member-only feature.

Click Here to join Eng-Tips and talk with other members! Already a Member? Login



News


Close Box

Join Eng-Tips® Today!

Join your peers on the Internet's largest technical engineering professional community.
It's easy to join and it's free.

Here's Why Members Love Eng-Tips Forums:

Register now while it's still free!

Already a member? Close this window and log in.

Join Us             Close