need to correct a typo on previous question
need to correct a typo on previous question
(OP)
in my previous question, i stated that my electric motor turns 3775 rpms. that is wrong. it turns 1775. sorry bout that.
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RE: need to correct a typo on previous question
Input speed 1775 rpm
ratio 37.5:1
Output speed of reducer 1775/37.5=47.333 rpm.
I assume that you have an 8" pulley on speed reducer driving a 12" pulley on conveyor drive pulley(spool)
Speed of Conveyor drive pulley(spool)=(47.333 X 8)/12=31.55 rpm
Check the forum list as this was not the best forum to raise this issue(see materials handling equipment engineering!!)
Ross
RE: need to correct a typo on previous question
Mike Halloran
Pembroke Pines, FL, USA
RE: need to correct a typo on previous question
RE: need to correct a typo on previous question