need to correct a typo on previous question 1

From your details:
Input speed 1775 rpm
ratio 37.5:1
Output speed of reducer 1775/37.5=47.333 rpm.

I assume that you have an 8" pulley on speed reducer driving a 12" pulley on conveyor drive pulley(spool)
Speed of Conveyor drive pulley(spool)=(47.333 X 8)/12=31.55 rpm

Check the forum list as this was not the best forum to raise this issue(see materials handling equipment engineering!!)

Ross

You can't edit a message directly, but you can Red Flag it, and in the dialog box that results, describe _specifically_ how you would like it changed, and chances are it will be changed, as if by magic.





Mike Halloran
Pembroke Pines, FL, USA

about the red flag.... thanks to mike halloran from crosstown

ross, i appreciate the double effort on my amended post. and i've copied your formula for future reference. i also submitted it under the gear and pulleys forum