CHANNEL/DIMENSIONS CHANNEL/DIMENSIONS LovinLife (Mechanical) (OP) 9 Apr 07 12:48 Can anyone tell me what the inside dimensions are on a 10" x 2.886 x .526 pc. of structural channel. Is there somewhere on the internet that lists these as well as for other sizes? Thanks everyone. RE: CHANNEL/DIMENSIONS UcfSE (Structural) 9 Apr 07 12:52 Channels are named by "depth x weight/foot" (in the USA). If you have that designation it would help you or others find it. RE: CHANNEL/DIMENSIONS COEngineeer (Structural) 9 Apr 07 12:54 That is got to be C10x25. the T is 8" RE: CHANNEL/DIMENSIONS doct9960 (Mechanical) 9 Apr 07 12:59 The channel you are talking about is a C10x25. What "inside dimensions" are you particularly looking for? Are your referring to the fillet at the intersection of the web and the flanges?Anyways, look into this website www.webcivil.comLook under Steel(US). RE: CHANNEL/DIMENSIONS LovinLife (Mechanical) (OP) 9 Apr 07 13:21 Sorry. Yes the weight is 25lbs.ft.I haven't went to the webcivil site yet but yes I'm looking for fillet and angles.Thank you. RE: CHANNEL/DIMENSIONS doct9960 (Mechanical) 9 Apr 07 13:50 TVS1962,I have an old edition of the ASD Manual of Steel Construction. Under Dimensions and Properties, it says, "American Standard channels (C) have a slope of approximately 16 2/3% (2 in 12") on their inner flange surfaces." It also says, "The properties of these rolled shapes are based on the smallest theoretical size fillets produced; dimensions for detailing are based on the largest theoretical size fillets produced. These properties are either exact or slightly conservative for all producers who offer them."Better grab a hold of the Manual. In there you will find "k" for a particular channel size. "k" is the distance from outer face if flange to web toe of fillet of rolled shape. For a C10x25, k = 1". The "T" dimension specified by COEngineeer is the difference between the depth (d) of the channel and 2 times "k" (i.e. for C10x25, 10"-2(1")=8" ) RE: CHANNEL/DIMENSIONS LovinLife (Mechanical) (OP) 9 Apr 07 14:04 Thanks to all of you for the help.