Hello AfricanElectric,
One way to do your emergency stop circuit is to use a 24 volt direct current power supply such as a power brick at the emergency stop end of the circuit. The emergency stop button would need to use double pole double throw ( form C ) contacts and at the motor end you would need a 24 volt DC relay preferably of the wide voltage range that can tolerate the 20 volt end voltage of a 24 volt battery. The normally closed contacts of the emergency stop button should interrupt both sides of the 24 volts from the power supply. The normally open contacts should be connected in parallel with each other and connected downstream of the normally closed contacts so as to short the line and discharge its capacitance when the emergency stop botton is pushed. The relay at the far end might need to be a 12 volts DC relay that uses a 7812 voltage regulator with some 1 microfarad capacitors for noise reduction and stabilization. Either voltage relay also needs a diode connected across the coil so that the diode is biased off when the DC is applied so that the diode will carry the inductive kick of the coil when turned off - this will increase the dropout time but only a little. The emergency stop button should be of the maintained contact type so that no harm will be done by a slow dropout time due to wiring capacitance.
An alternate way to do a failsafe emergency stop circuit is to use a UL Listed fire alarm or burglar alarm box at your ski lift motor controller.
Failsafe circuits for fire alarms and burglar alarms use the Wheatstone Bridge principle to detect normal, shorted, and open circuit conditions. Three of the bridge resistors, usually 10,000 ohms each, are located in the alarm panel. The fourth resistor is located at the far end of the circuit.
In a normally closed circuit, what is used for lead tape on windows and so forth, an open circuit condition triggers the alarm and s short circuit triggers the fault alert. A circuit resistance of 10,000 ohms indicates normal conditions.
For a normally open circuit the shorted condition is the alarm condition and an open circuit is the fault condition. For 4 wire circuits that supply smoke detectors and motion detectors there is a relay at the far end of the circuit that opens the resistor upon failure of the control power. A more sophistocated relay would be an interval relay that altenates between 10,000 ohms and open circuit so that a bad relay can be detected.
For either method you would need to use direct burial rated telephone cable that is filled with a waterproofing gel. 19 gauge telephone cable would be a good investment because that is the largest gauge telephone cable next to open wires. You can get direct burial cable that is 19 gauge with as few as 3 pairs of wire and a layer of steel to deter gophers and tree roots from breaking the cable.
You will need 2 kilometers of cable, maybe more. When direct burying small telephone cables you need to pay out 1.5 to 2 feet of cable for each foot of trench. (1.5 to 2 meters of cable per meter of trench for metric.) This is so that the cable can conform to the bottom of the trench when backfilling. If you are running the cable overhead using a steel messenger cable for support you will need to leave lots of slack when stringing it during the summer and leave a generous slack loop at each support pole.
You will also need a telephone protector block at each end. What you can do with the extra wire pairs is to put in a dedicated telephone circuit and maybe a buzzer or other telegraph circuit. You also need to ground one end or the other of each circuit.
Your resistor at the far end of the fire alarm or burglar alarm circuit might need to be a variable resistor to compensate for wire resistance. Wire resistance will be lower during the winter but if you can bury the cable 1 to 1.5 meters ( 3 to 5 feet ) deep you will have less temperature swing and fewer other problems.
Mike Cole, mc5w@earthlink.net