MotoGP
Marine/Ocean
- Jul 14, 2003
- 23
Greetings and gratitude to all who are intrested in, yet another, bolt-torque plea-for-help:
Please take heart in that I have read the previous threads that pertain to bolt torque value calculations. As such, I have learned a lot about just how little I know about fasteners.
The challenge for me, obviously having precious little native ability in this area, is to understand how the maker of a Hose Handling Crane, installed on the weather deck of a SuexMax Crude Oil Carrier, arrived at: a) the clamping force for the bolts utilized in the subject application, and b) how I might arrive at a torque value based upon the information provided in the drawing.
Here goes...
One (1) slewing gear, two-part assembly (upper and lower halves), is clamped by the installation of:
A) 68 Stud Bolts, all DIN 938 Mod, M36X310 (N.B. ~ 34 of these bolts are installed on the upper half of the subject gear, and require nuts...the other half are installed in tapped holes and do not require nuts to secure them).
B) Washers, two (2) each for each of thirty-four (34) of the above bolts, and (1) each for the remaining thirty-four (34), all DIN 6916 Mod., Dia.37/66
C) One (1) Stud Nut for thirty-four (34) of the above bolts, all DIN 6915-10 Mod., M36.
D) Manufacaturer Drawing shows that each of the bolts, when installed properly (in a clockwise manner), is to apply a 610KN "clamping" force on the slewing gear halves.
It would be great to understand how the "clamping" force was derived, and subesquently the size of the fastener.
It would be AN ANSWER TO PRAYER to understand how to obtain the correct torque value from the information provided, especially that of the "lower" bolts (i.e., the bolt, with one washer, that gets threaded into the tapped hole).
Any constructive information that you could provide would meet with eternal gratitude (no kidding!).
Cheers,
Pete
To all fastener "gurus":
Please envision the question applicant bowing torso forward, and with extended arms repetitively shouting, "I'm not worthy, I'm not worthy...."
Please take heart in that I have read the previous threads that pertain to bolt torque value calculations. As such, I have learned a lot about just how little I know about fasteners.
The challenge for me, obviously having precious little native ability in this area, is to understand how the maker of a Hose Handling Crane, installed on the weather deck of a SuexMax Crude Oil Carrier, arrived at: a) the clamping force for the bolts utilized in the subject application, and b) how I might arrive at a torque value based upon the information provided in the drawing.
Here goes...
One (1) slewing gear, two-part assembly (upper and lower halves), is clamped by the installation of:
A) 68 Stud Bolts, all DIN 938 Mod, M36X310 (N.B. ~ 34 of these bolts are installed on the upper half of the subject gear, and require nuts...the other half are installed in tapped holes and do not require nuts to secure them).
B) Washers, two (2) each for each of thirty-four (34) of the above bolts, and (1) each for the remaining thirty-four (34), all DIN 6916 Mod., Dia.37/66
C) One (1) Stud Nut for thirty-four (34) of the above bolts, all DIN 6915-10 Mod., M36.
D) Manufacaturer Drawing shows that each of the bolts, when installed properly (in a clockwise manner), is to apply a 610KN "clamping" force on the slewing gear halves.
It would be great to understand how the "clamping" force was derived, and subesquently the size of the fastener.
It would be AN ANSWER TO PRAYER to understand how to obtain the correct torque value from the information provided, especially that of the "lower" bolts (i.e., the bolt, with one washer, that gets threaded into the tapped hole).
Any constructive information that you could provide would meet with eternal gratitude (no kidding!).
Cheers,
Pete
To all fastener "gurus":
Please envision the question applicant bowing torso forward, and with extended arms repetitively shouting, "I'm not worthy, I'm not worthy...."