Friction against the helix is the main component of the torque. Take a 14" diameter helix with a 3" pitch and an area of 1.05 sq. ft. on a minimal shaft in a clay with a cohesion of 5000 PSF. The helix area times the cohesion of the soil times the cos(avg. helix angle) times the alpha friction factor x midpoint of area will give you a torque. 1.05 SF x 9 x 5000 x cos(11*) x 0.3 x (.58' x .707)= 5700 lbs-ft. If pile capacity is 1.05 x 9 x 5000 = 47,250# per the Standard Bearing Capacity Equation then Kt = 47,250/5700 or 1/(cos(11*) x 0.3 x (.58' x .707))or 8.3.