To be even more clear, consider a flat long RC sleeper beam made of short quadrangular elements to which shear is relevant, say width of element to thickness ratio=2. For each and every element when solving for equilibrium if considered thin shell or plate element (without accounting shear effect), moment effects will be over-represented in each and everyone of them. If you take one, then the following towards one support, the effect happens again in it, moment will be over-represented since the shear deformation won't be there to diminish the bending energy intake required to equilibrate the external forces.
Hence, if you choose thin elements where shear needs be accounted element per element, as a result of the dimension to thickness ratio, you will get the moments bigger than they must (as it is seen when more exactly determined), and shear under-represented, i.e., less shear than required. To have more moment won't do harm, but having less shear than what to the case pertains risks brittle fractures that are better to avoid and so either you can rely in thin elements for your case or you better use thick ones to avoid this risk.