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Taper

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xrobc

Mechanical
Joined
Jan 26, 2009
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4
Please could someone offer me some help on tapering a face/edge.

I am trying to put a 3 degree taper along the length of the revolved feature of the attached model, but no matter what I try I cannot do it.

Please can someone help!

Thanks
 
Are you talking about the curved feature?

You are in NX5 ... right?
 
Correct on both counts

The curved feature and NX5.
 
Robert,

Do you mean the curved spout that you have two copies of at features 19 and 20?

In which vector direction do you want to apply taper to that spout if indeed that is your request?

If you wish to apply such a taper more or less along its axis which is to say around the corner then I have supplied a possible solution which is rather an approximation of your request but different than what you may expect. The idea that you can define a reduction in diameter around a corner that takes account of an linear concept such as you might describe in terms of angularity seems incompatible with the geometry in question, but by all means post back to explain you criteria clearly if you're not satisfied with this interpretation.

If I may also suggest in noticing that you're using a very early version of NX-5 that you get the latest version from the GTAC site since a lot early bugs have since been fixed, and the later versions had improved functionality. Also when posting on the forum it helps if you indicate the version you're using for the benefit of those of us trying to respond who may be using an earlier version and therefore cannot help.

Best Regards

Hudson

www.jamb.com.au

Nil Desperandum illegitimi non carborundum
 
 http://files.engineering.com/getfile.aspx?folder=401c415f-32e3-4447-aaca-408318b5127c&file=Watering_Can.prt
Hudson

What I am trying to effectively do is extrude Sketch_006 (the circle) along sketch_005 with a 3 degree taper angle (as per the attached PDF).

I have managed to produce it in AutoCAD by using the Extrude command and extruding along a path and because its a extrude I can apply the taper angle.

Any thoughts?

Thanks

Rob
 
 http://files.engineering.com/getfile.aspx?folder=c6f1cace-03b0-4e08-85bd-cb4359dfd5b2&file=can2a.pdf
Robert,

I've attached a version of the file with everything parametric including a couple of features intended to demonstrate the analysis of the geometry that I created. Rather than explain in great detail you will possibly grasp what has been done better by analysing the file itself. The result does I hope go some way to duplicating the intent of what you requested.

Best Regards

Hudson

www.jamb.com.au

Nil Desperandum illegitimi non carborundum
 
 http://files.engineering.com/getfile.aspx?folder=641a4014-8ae8-45c5-b716-0abe765da150&file=Watering_Can.prt
OK, I took a slightly different approach than Hudson took, but the result is a fully parametric tapered spout which you can enter the exact angle of the taper by editing the value the Expression 'Spout_Taper'. Note that this also updates if the diameter of the base of the spout or the angle of the curved segment is modified.

And as Hudson stated, I'll leave the details for you to figure out, but once you grasp the approach which I've taken I think you will see where this will give you literally what your .pdf file showed.

John R. Baker, P.E.
Product 'Evangelist'
Product Design Solutions
Siemens PLM Software Inc.
Cypress, CA

To an Engineer, the glass is twice as big as it needs to be.
 
John,

Interesting method I like it! I guess the part that I liked best was that for all intents and purposes it is the same result. I used an expression formula to drive the offset of the curve, and a line to create the adjacent side of the triangle. Therefore both end circles are the same size. The only thing I tried to do differently in the sweep was to control the scaling with a vector curve and that made a technical difference only at the third or fourth decimal point.

Best Regards

Hudson

www.jamb.com.au

Nil Desperandum illegitimi non carborundum
 
John

If I have read what you have done corrctly then you have:

Drawn the flatened tapered spout in Sketch007 where the length of the flat is measuerment 27.

You then used this to calculate the end diameter (2*measurement 27) place on the datum plane (24) so with the start and end diameters you have swept from one to the other along the curved profile (sketch 13).

Rob
 
Yes, that's about it. I basically 'reverse engineered' what the orthographic view, as illustrated in your .pdf file, of the spout would have been. Which is also somewhat along the lines of Hudson's approach, it's just that he 'trigged' out the value of the end circle while I derived it from the constructed 'profile'.

John R. Baker, P.E.
Product 'Evangelist'
Product Design Solutions
Siemens PLM Software Inc.
Cypress, CA

To an Engineer, the glass is twice as big as it needs to be.
 
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