dannyypk
Structural
- Sep 29, 2004
- 26
I am designing a concrete footing for a 26'tall sign. The overturning moment is about 80.97 k-ft.The ultimate momeny Mu = 1.5 * 80.97 k-ft = 121.5k-ft
I have a question about the design of that footing. The client wants to embedd the HSS tube steel directly burial into the concrete. I would have to design the footing to resist the overturning moment and the thickness to resist the wind base shear.
The footing now is mainly designed for resisting the overturning moment and the vertical load is so small. I would like to see if anyone can help me with designing a footing with high moment and the small vertical load.
q = 1500 psf (assumed) = Pu/A + Mu/S
The above equuation seems not working in the above situation.
I have a question about the design of that footing. The client wants to embedd the HSS tube steel directly burial into the concrete. I would have to design the footing to resist the overturning moment and the thickness to resist the wind base shear.
The footing now is mainly designed for resisting the overturning moment and the vertical load is so small. I would like to see if anyone can help me with designing a footing with high moment and the small vertical load.
q = 1500 psf (assumed) = Pu/A + Mu/S
The above equuation seems not working in the above situation.