Today at 9:04 AM #1 K kev2632 Electrical Apr 7, 2025 6 Hi, I'm just learning and I've got what is probably a stupid question here but I'd appreciate the help and a simple basic explanation of this. Why is the KA rating fault current of a low voltage 440v switchboard higher than the high voltage 6.6KV ? Thanks
Hi, I'm just learning and I've got what is probably a stupid question here but I'd appreciate the help and a simple basic explanation of this. Why is the KA rating fault current of a low voltage 440v switchboard higher than the high voltage 6.6KV ? Thanks
52 minutes ago #2 waross Electrical Jan 7, 2006 28,254 The ASCC, Available Short Circuit Current is the rated full load current divided by the transformer percent impedance voltage. You do the math: A 1000 KVA transformer; what is the rated secondary current at 440Volts and at 6.6kVolts? Upvote 0 Downvote
The ASCC, Available Short Circuit Current is the rated full load current divided by the transformer percent impedance voltage. You do the math: A 1000 KVA transformer; what is the rated secondary current at 440Volts and at 6.6kVolts?
