In dilute aqueous solution, at neutral and alkaline pH, chromic acid is present as the yellow chromate ion, CrO4-2. The neutralization may be written
H2CrO4 +2 NaOH = Na2CrO4 + 2 H2O
If your initial solution is acidic, you will observe a color change upon neutralization, as the orange-red dichromate ion Cr2O7-2 reacts to form yellow chromate:
Cr2O7-2 + OH- = 2 CrO4-2 + H+
The neutralization reaction for an initially mildly acidic solution* is therefore
H2Cr2O7 +4 NaOH = 2 Na2CrO4 + 3 H2O
Both sodium chromate Na2CrO4 and sodium dichromate Na2Cr2O7 (which can be formed at strongly acidic pH*) are highly soluble. For removal of hexavalent Cr as part of a wastewater treatment process, it is best to either remove it via ion exchange or reduce it to trivalent Cr prior to neutralization.