PEVT - One way to approach this problem is to make simplifying assumptions that will result in a reasonable, approximate answer. I'll go over how do this my hand, using old style ASD (9th Ed. AISC) - perhaps the calcs can be speeded up with software. Be warned, the method is tedious
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1. Based on published dimensions and properties of S6x12.5, make a simplified shape from three rectangles - two flanges plus web. See Page 1 of the attachment.
2. Calculate accuracy of the area and section modulus of the simplified shape. Results (98.5%+ accurate) are summarized on Page 1. Note: Since the shape is symmetric about the X-axis, section modulus can be calculated directly - this will be important later.
3. Subtract the diameter of the pair of 9/16" holes from the width of the bottom flange. Then assume that this reduced width flange is continuous (the holes are now gone). See Page 2.
4. Calculate the section modulus for the equivalent, modified S6x12.5. Since this section is NOT symmetric about the X-axis, section modulus cannot be calculated directly. Compute the area, moment of inertia, then the section modulus.
5. Assuming the S6x12.5 is simply supported, the reduced section bottom flange is the tension flange. Therefore the beam can be loaded to full allowable bending stress (say, 24 KSI for A36 steel).
6. To calculate bending stress at the location of the holes, position the trolley so that one wheel is directly over the holes. The other wheel is to the side that puts it closest to the center of the beam. This will give maximum bending stress at that spot compared to ANY location of the trolley along the length of the beam. Also include bending stress, at the location of the holes, from the the beam's self weight (a uniform distributed load). See Page 3 of the attachment.
The result should give a reasonable estimate of bending stress, at the location of the holes.
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