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Pipe radial expansion due to internal pressure 4

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Philip54US

Civil/Environmental
Jul 10, 2008
1
I would like to calculate the increases in internal diameter and external diameter in a pipe full of water when the pipe is pressurized.

Could anybody provide the formulas or advise where I can find them?

The ratio R/t is 8.625.

Thanks
 
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The hoop stress will give you the change in length of the dianeter, which in turn gives the change in radius.

With r/t>5 Hoop stress can be taken as pressure*radius/thickness
 
[Δ]r=pr[²]/Et. You may want to think about thermal expansion/contraction as well.
 
Depending on the details, there may be a minor correction for lengthwise effects as well.

If the pipe is out-of-round, it will tend to round up when pressurized.
 
Hi Philip54US

If your pipe wall is more than 1/10 of the radius which I suspect it is then you need to use Thick Walled Cylinder Theory see page 6 of this link titled "Constitutive Equations".

regards

desertfox
 
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