RonNicholls
Automotive
- Feb 27, 2013
- 1
Trying to dimension a print properly and came across an intriguing portion of the ASME Y14.5-2009 standard.
I have always understood that if you use (for example) 3 decimal places in the "nominal" dimension, then the "tolerance" should have the same number of decimal places (example: 33.3" +/- 0.5). This would match what is stated in "INCH" dimensioning in the ASME14.5-2009 standard (section 2, pages 25/26).
It does not seem applicable to metric tolerancing if you read the ASME standard. It seems you can ues as many decimal points in the nominal and tolerance as you want....meaning they don't have to match. You could have 25.3mm +/- 0.123456789 as a callout.
How does this make sense & does anyone see it differently?
I have always understood that if you use (for example) 3 decimal places in the "nominal" dimension, then the "tolerance" should have the same number of decimal places (example: 33.3" +/- 0.5). This would match what is stated in "INCH" dimensioning in the ASME14.5-2009 standard (section 2, pages 25/26).
It does not seem applicable to metric tolerancing if you read the ASME standard. It seems you can ues as many decimal points in the nominal and tolerance as you want....meaning they don't have to match. You could have 25.3mm +/- 0.123456789 as a callout.
How does this make sense & does anyone see it differently?