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Minimum Clamp Force for Multiple Shearing Plane Joint - Advice

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OMacS

Mechanical
Sep 14, 2018
1
Hi all,
I would really appreciate some guidance on determining the minimum clamp load for a joint with more than one interface.

VDI 2230 gives the minimum clamp load to provide friction grip against shear slip as:

Fmin = (F load) / (q * C.O.F min)

Where q is the number for friction interfaces in the joint, COF min is the coefficient of friction at the interface, and F load is the transverse load. Link to exact formula provided below.

I have only found examples for single friction interface joints, where q=1 so the formula is self explanatory. But I need to assess joints with multiple friction interfaces and here I am unsure how to proceed.

The formula seems to suggest I would take the lowest COF and multiple it by the number of interfaces. But this would lead to a smaller required preload compared to a single interface joint.

Does anyone have experience on how to treat this type of joint?

Help much appreciated.

Best Regards,

Oliver
 
 https://files.engineering.com/getfile.aspx?folder=0be7e4f7-6d92-4e88-969f-123b00a3c8d4&file=VDI2230-P20snip.JPG
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