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LPDME dimethyl ether from syngas

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carletto57

Chemical
Joined
Oct 9, 2007
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Hy all,
I try to do the implant as in the object.
I know only the mole ratio of CO e H2 and this is 2:1, this is the out of syngas.
My problem starts here, because I don't know how I can do the reaction balance in my reactor because all reaction are equilibrium:

CO+2H2 = CH3OH
2CH3OH = CH3OCH3 + water
CO+H2O=CO2+H2

All of this reactions, are in the reactor, so how I can size the reactor? I supposed that all of the reaction product out of the reactor.

Can please someone help me?

Thank you all
Carlo from Italy (sorry for my bad english).
 
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