lifting force of a beam

[harrytos23]

Hi there,

I just have question about how much force is needed to lift the beam at point C.

Point B will be the hinge location (rotation allowed but no x and y displacement), Point C is the spot where I want to lift the beam and X would be the overall length of the beam.
Total weight of the beam is 1498 lbs.

Am I missing/not including needed variable to calculate it? Thank you.

 

[GregLocock]

If I make all the spherical cow assumptions yes you have included enough information.

 

[Snickster]

Sum moments about point "B" due to weight of beam and reaction force at "C". Solve for reaction force at "C".

Sum forces to get reaction force at "B".

 

[3DDave]

The main assumption is that the beam is of uniform weight/mass along its length and the weight/mass of the plates that are carrying the load from the beam to the supports is negligible or is included in the overall weight/mass of the beam.

 

[rb1957]

1) don't double post.

2) where is the weight of the beam acting ? yes, we'd assume uniform weight distribution, so answer is x/2 ... but your other post says there's a concentrated mass at the far end, so not uniform, so treat the beam and the mass separately (in 4) below).

3) you want an algebraic answer (not a number) ?

4) do you understand "sum moments about B" ?

 

[MintJulep]

Point D, the anchor point of the cylinder will become important as you look for a full system solution.

 

[Ron247]

If I make all the spherical cow assumptions yes you have included enough information.

I agree you have included enough information, but I arrived at this conclusion independently, without spherical cow theory, I used Big Potato theory.
You just need to use statics now.

 

[Ron247]

I think most people are assuming you mean to "start lifting the beam". Once you start pivoting about the hinge, the force will change depending on how your lift cylinder position responds to the relocation of point C