To illustrate the inrush effect, consider a single-phase transformer energized at t=0 with an ideal voltage source. Therefore, when the transformer is energized, the transient voltage generated is e(t)= d M(t)/dt.
Where: e(t) = source voltage; M(t) = magnetic flux linkage of the transformer.
For initial cond @ t = 0; M(0) = a.
Voltage Source : e(t)= Vm. Cos(wt+Q).
The solution is: M(t)= (a-Vm/w. sinQ) + Vm/w.sin(wt+Q).
The first term is the dc bias. For steady state, Q=0 the inrush current is 1% of rated current, while for Q=pi/2 it may reach a peak of 800 % of rated current or higher. The inherent system resistance forces the inrush current to decay slowly.
See also the following post in this topic:
thread238-10885