MThomey
Structural
- Nov 8, 2006
- 6
I am working on a shear pin design in a sawmill application. A sorter mechanism that holds lumber travels vertically up and down an HSS column. The sorter cradle and full load of lumber could fall a distance of approximately 12" if the hydraulics fail. A steel pin through the HSS column stops the fall of the cradle (see attached sketch). Using Blodgett's formula (Section 2.8-3, paragraph 5), I get a huge spring constant (K) as the shear deformation/deflection of the pin + column shortening are infintesimal (0.0128"). This produces an astronomical force of 1065 kips based on 12" fall & 24 kip body weight. Half of that goes to each column (532.5 k) and is way in excess of the column capacity. What am I missing? Is there a better way to determine the impact force for this application? Thanks.