I need a sanity check

[ribguys]

Say you've got a fixture on a wing that undergoes a 10g vertical maneuver going through the CG of the fixture, and on the end of the fixture is an object "d" on a linkage distance "a" from the fixture. If you need to use torque to resist that loading scenario the torque required would just be T = 10*Md*g*a, right?

 

[Lnewqban]

What b has to do with your problem?

Does object d can rotate around pin on the plane of the drawing?

If so, is that rotation what you try stopping with a moment applied on the pin?

"Where the spirit does not work with the hand, there is no art." - Leonardo da Vinci

 

[ribguys]

b is the distance from CG to the end of the fixture.

Yes, object d can rotate around the pin. Lets say you had a motor directly on the pin that reacted to the G forces to keep object d in it's orientation.

 

[desertfox]

Hi

I might be misunderstanding the problem but the direction of the forces drawn result in a couple acting around the pin d

if you take moment about pin d then the resisting moment in my mind should be equal to (Md)g*a + 10*b

“Do not worry about your problems with mathematics, I assure you mine are far greater.” Albert Einstein

 

[LittleInch]

Only correct, IMO, if the CG of item d is exactly at the connection point between it. At the initial point it doesn't matter, but if it moves them the moment would increase or if the bar didn't go vertically up.

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