Hallo.
EE here. Out of my element.
I am updating and old system.
I have built all the electrical controls (plc, yada, yada) for a new hydraulics system. The system runs five double acting rams. The rams are evenly spaced at 100 thru 180 feet from the pump/control package. This is down 1/2 inch hoses.
The rams are 2" bore, 1" rods with 13.62" strokes.
A stroke is supposed to take 27 seconds.
Now my problem is this:
The existing system terminates a cycle(opening or closing) by a limit switch. Some of the limit switches have failed. Some always stay made, some never make. I was requested to "make do" with a pressure switch. In other words when the ram dead-heads the pressure will climb rapidly to the pump's relief pressure. I expected to have a pressure switch in the pump circuit that could provide this input and there is one. It makes on rising pressure at 2,200psi. Another switch makes on falling pressure of 1800psi.
There is also a 1/2 gallon accumulator precharged with 1200psi Nitrogen.
The pump is a 0.67GPM at 2,000psi.
I asked what the low pressure switch was for. I was told by the guy who provided the hydraulics, "The pump may come on and if it charges the accumulator up to 2,200psi while a cycle is running then you'll want to turn off the pump. When the pressure in the accumulator drops to 1,800psi you'd want to turn the pump back on. Cycling until the limit switch actuates" ... Doh!
Now I recognize that if there is a large enough restriction between the accumulator and the rams then the pump could well end up providing more fluid then the ram/system can accept and you would end up charging the accumulator to the 2,200psi point BEFORE the stroke is complete. But if this cycling mode occurs I don't see how I can use the pressure to terminate a cycle!?!?
Looking at the info I have provided is it possible to estimate whether I can expect cycling?
Near as I can figure the worst case possibility is retraction.
2 inch bore = 3.14sqin
1 inch ram = 0.78sqin
Area = 3.14 - 0.78 = 2.34sqin
Volume = 2.34sqin x 13.6in = 32in3
32in3 = 0.138gallon
0.138gal / 27sec/60sec/min = 0.30GPM
Looks like I could have a problem??![[bugeyed] [bugeyed] [bugeyed]](/data/assets/smilies/bugeyed.gif)
Any help greatly appreciated.
Keith Cress
Flamin Systems, Inc.-
EE here. Out of my element.
I am updating and old system.
I have built all the electrical controls (plc, yada, yada) for a new hydraulics system. The system runs five double acting rams. The rams are evenly spaced at 100 thru 180 feet from the pump/control package. This is down 1/2 inch hoses.
The rams are 2" bore, 1" rods with 13.62" strokes.
A stroke is supposed to take 27 seconds.
Now my problem is this:
The existing system terminates a cycle(opening or closing) by a limit switch. Some of the limit switches have failed. Some always stay made, some never make. I was requested to "make do" with a pressure switch. In other words when the ram dead-heads the pressure will climb rapidly to the pump's relief pressure. I expected to have a pressure switch in the pump circuit that could provide this input and there is one. It makes on rising pressure at 2,200psi. Another switch makes on falling pressure of 1800psi.
There is also a 1/2 gallon accumulator precharged with 1200psi Nitrogen.
The pump is a 0.67GPM at 2,000psi.
I asked what the low pressure switch was for. I was told by the guy who provided the hydraulics, "The pump may come on and if it charges the accumulator up to 2,200psi while a cycle is running then you'll want to turn off the pump. When the pressure in the accumulator drops to 1,800psi you'd want to turn the pump back on. Cycling until the limit switch actuates" ... Doh!
Now I recognize that if there is a large enough restriction between the accumulator and the rams then the pump could well end up providing more fluid then the ram/system can accept and you would end up charging the accumulator to the 2,200psi point BEFORE the stroke is complete. But if this cycling mode occurs I don't see how I can use the pressure to terminate a cycle!?!?
Looking at the info I have provided is it possible to estimate whether I can expect cycling?
Near as I can figure the worst case possibility is retraction.
2 inch bore = 3.14sqin
1 inch ram = 0.78sqin
Area = 3.14 - 0.78 = 2.34sqin
Volume = 2.34sqin x 13.6in = 32in3
32in3 = 0.138gallon
0.138gal / 27sec/60sec/min = 0.30GPM
Looks like I could have a problem??
![[bugeyed] [bugeyed] [bugeyed]](/data/assets/smilies/bugeyed.gif)
Any help greatly appreciated.
Keith Cress
Flamin Systems, Inc.-