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Hold Time

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I need to hold a product (ie.milk) for 360 seconds @ 90C
in a holding tube.
The tube diameter is 0.75" and the flowrate is 300L/h.
What length of tubing will I need to achieve this? I've
calculated 6315 meters, but that seems like alot! Can
someone help me out here.
Thanks.
 
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The pressure in the tubing is about 600psi.
 
The length is calculated by multiplying flow velocity times the required hold time. In your case, 300 L/hr is equal to 5.085 in^3/s. The cross sectional area of 0.75" diameter is 0.442 in^2. Dividing the flow rate by the pipe area gives a fluid velocity of 11.51 in/s. Multiplying the fluid velocity by the hold time give a length of 4114 inches, or 105.2 m, or 345.3 ft.
 
Thanks butelja.
I made a stupid mistake dividing by 60 to get seconds
instead of 3600 (from L/h ---> L/s)
 
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