This is similar to the prior case for NaH.
Data are from Perry’s, 7th ed., Table 2-220.
For potassium + water, the stoichiometric reaction (no excess water) is
K(s) + H2O(l) --> KOH(s) + ½ H2(g)
&[ignore]Delta[/ignore];HRxn, 25 C = -102.02 + 0 – 0 – (-68.32) = -33.7 kcal/mol
For potassium + water, with excess water (value is for final solution KOH in 400 H2O), the reaction is
K(s) + H2O(l) --> KOH(aq, 400H2O) + ½ H2(g)
&[ignore]Delta[/ignore];HRxn, 25 C = -114.96 + 0 – 0 – (-68.32) = -46.64 kcal/mol
For CaH2, the stoichiometric reaction (no excess water) is
CaH2(s) + 2 H2O(l) --> Ca(OH)2(s) + 2 H2(g)
&[ignore]Delta[/ignore];HRxn, 25 C = - 235.58 + 0 – (-46) – 2(-68.32) = -52.94 kcal/mol
For CaH2, the reaction with excess water is
CaH2(s) + 2 H2O(l) --> Ca(OH)2(aq, 800H2O) + 2 H2(g)
&[ignore]Delta[/ignore];HRxn, 25 C = - 239.2 + 0 – (-46) – 2(-68.32) = -56.56 kcal/mol
These reactions may be vigorous, and possibly explosive without excess water. Lots of heat (even more if the H2 ignites!). What is your application?