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Heat loss in cabinet

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MvBurgh

Chemical
Dec 8, 2008
1
Hi All,

Im trying to calculate the heater sizing for an intertec cabinet that will be placed in a freezing location.

However im getting weird results based on:

k.A
--- * dT
L

I'm getting for a small window (0.36 m2) a heat-loss of 1440W.
Thermal conductivity of the glass is 0.8 W/m.K

Can someone indicate where im going wrong?

Best Regards,
Martin
 
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