Kevds122
Structural
- Sep 11, 2015
- 1
Hey everyone.
I currently work for a steel fabrication company and am developing a set of calculations regarding full and half depth beam stiffeners. It is not uncommon to get structural design drawings from the engineer of record that show stiffeners with welding on both sides of the stiffeners to the web and flange(s), which is a bit excessive in my opinion and can be reduced.
The calculations that I am looking to develop would involve determining the ultimate strength of the stiffener plates and then designing welds based on the strength of the stiffeners to request a reduced weld size with a possible lesser length than the weld that I described in the paragraph above (less weld = less labor/less equipment use = saved costs).
The problem I run into is determining the wording in J10-8 of the AISC Manual (14th Edition, pg. 16.1-138)
"Stiffeners required to resist tensile concentrated forces shall be designed in accordance
with the requirements of Section J4.1 and welded to the loaded flange and the
web. The welds to the flange shall be sized for the difference between the required
strength and available strength. The stiffener to web welds shall be sized to transfer
to the web the algebraic difference in tensile force at the ends of the stiffener.
Stiffeners required to resist compressive concentrated forces shall be designed in
accordance with the requirements in Section J4.4 and shall either bear on or be
welded to the loaded flange and welded to the web. The welds to the flange shall be
sized for the difference between the required strength and the applicable limit state
strength. The weld to the web shall be sized to transfer to the web the algebraic difference
in compression force at the ends of the stiffener. For fitted bearing stiffeners,
see Section J7."
My assumption would be to use the follow equations for the strength of the stiffener plates:
Full depth stiffener plates
Rn = 1.8(Fy)(Apb) (Equation J7-1)
Half depth stiffener plates
Rn = (Fy)(Ag) (Equation J4-6)
I could then design the welds based on these values.
Any help would be greatly appreciated!!!!
I currently work for a steel fabrication company and am developing a set of calculations regarding full and half depth beam stiffeners. It is not uncommon to get structural design drawings from the engineer of record that show stiffeners with welding on both sides of the stiffeners to the web and flange(s), which is a bit excessive in my opinion and can be reduced.
The calculations that I am looking to develop would involve determining the ultimate strength of the stiffener plates and then designing welds based on the strength of the stiffeners to request a reduced weld size with a possible lesser length than the weld that I described in the paragraph above (less weld = less labor/less equipment use = saved costs).
The problem I run into is determining the wording in J10-8 of the AISC Manual (14th Edition, pg. 16.1-138)
"Stiffeners required to resist tensile concentrated forces shall be designed in accordance
with the requirements of Section J4.1 and welded to the loaded flange and the
web. The welds to the flange shall be sized for the difference between the required
strength and available strength. The stiffener to web welds shall be sized to transfer
to the web the algebraic difference in tensile force at the ends of the stiffener.
Stiffeners required to resist compressive concentrated forces shall be designed in
accordance with the requirements in Section J4.4 and shall either bear on or be
welded to the loaded flange and welded to the web. The welds to the flange shall be
sized for the difference between the required strength and the applicable limit state
strength. The weld to the web shall be sized to transfer to the web the algebraic difference
in compression force at the ends of the stiffener. For fitted bearing stiffeners,
see Section J7."
My assumption would be to use the follow equations for the strength of the stiffener plates:
Full depth stiffener plates
Rn = 1.8(Fy)(Apb) (Equation J7-1)
Half depth stiffener plates
Rn = (Fy)(Ag) (Equation J4-6)
I could then design the welds based on these values.
Any help would be greatly appreciated!!!!