jjv2006
Civil/Environmental
- Apr 15, 2006
- 23
I am trying to design a oil water separator and need to figure out a worst case concentration for a spill of 20,000 gallons of No. 6 oil say within a time of 4 hours. This is mixed with a peak flow of 7.5 MGD. I was able to do the following:
20000 gallons/hour = 5000 gallons/hour and 7.5 MGD is almost 100,000 gallons/hour.
To calculate the concentration in ppmv :
(5000/105000)*10^6 = 47620 ppmv.
How can I convert this above value into mg/l or a mass based flow rate.
Other information. Specific Gravity of No.6 oil = 0.98.
Density of Wastewater = 980 kg/m3.
Any help is appreciated or any texts that can be of use will also be useful.
Thanks in advance.
20000 gallons/hour = 5000 gallons/hour and 7.5 MGD is almost 100,000 gallons/hour.
To calculate the concentration in ppmv :
(5000/105000)*10^6 = 47620 ppmv.
How can I convert this above value into mg/l or a mass based flow rate.
Other information. Specific Gravity of No.6 oil = 0.98.
Density of Wastewater = 980 kg/m3.
Any help is appreciated or any texts that can be of use will also be useful.
Thanks in advance.