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Flow monitoring
- Thread starter moggie
- Start date
You need:
The rotational speed of the screw.
The number of turns over the length of the screw (could be 5-1/4 or some other fraction)
Divide the weight of all the material in the screw that you have already by the number of turns over the length.
That gives you the amount in one "section" of the screw.
Now one "section" is advanced every revolution. So the transfer weight of one section times the rotational speed will give you the answer.
Somebody check me here..
Keith Cress
Flamin Systems, Inc.- - kcress@<solve this puzzle>
The rotational speed of the screw.
The number of turns over the length of the screw (could be 5-1/4 or some other fraction)
Divide the weight of all the material in the screw that you have already by the number of turns over the length.
That gives you the amount in one "section" of the screw.
Now one "section" is advanced every revolution. So the transfer weight of one section times the rotational speed will give you the answer.
Somebody check me here..
Keith Cress
Flamin Systems, Inc.- - kcress@<solve this puzzle>
I don't think it is so simple. If the material [M] doesn't
touch the housing, there is no axial force - the M rotates
with the screw in place.
This means that the layer will move at different axial speed. The M closer to the axis will rorate with the srew
and advance axially only slowly - the outer layers
will rotate slower and advance faster.
If course there is some mixing between the layers,
further complicating the picture.
Why not just simply measure it ?
Plesae read FAQ240-1032
<nbucska@pc33peripherals.com> omit 33 Use subj: ENG-TIPS
touch the housing, there is no axial force - the M rotates
with the screw in place.
This means that the layer will move at different axial speed. The M closer to the axis will rorate with the srew
and advance axially only slowly - the outer layers
will rotate slower and advance faster.
If course there is some mixing between the layers,
further complicating the picture.
Why not just simply measure it ?
Plesae read FAQ240-1032
<nbucska@pc33peripherals.com> omit 33 Use subj: ENG-TIPS
smoked: Your solution assumes that the M is prevented
from rotating which is true only for the layer in contact with the housing -- especially if the housing has grooves etc. -- but certainly not true for the material adjacent
to the axis.
Plesae read FAQ240-1032
<nbucska@pc33peripherals.com> omit 33 Use subj: ENG-TIPS
from rotating which is true only for the layer in contact with the housing -- especially if the housing has grooves etc. -- but certainly not true for the material adjacent
to the axis.
Plesae read FAQ240-1032
<nbucska@pc33peripherals.com> omit 33 Use subj: ENG-TIPS
Were it me, I'd just measure the actual rate at which the material comes out for a given mass over a couple of differents speeds and a couple of masses for a given speed and use that info to derive your transfer equation empirically.
Augers are funky things because material slides around the outside of the flighting and (in our case) bounces over the top of the flighting in an open trough.
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How much do YOU owe?
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Augers are funky things because material slides around the outside of the flighting and (in our case) bounces over the top of the flighting in an open trough.
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How much do YOU owe?
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