I don't see in your block diagram where the condensate is removed, so I'm going to go out on a limb and assume that it stays with the pulp.
How is the "temp after = ?" different from the bleach tower temperature? This confuses me. It looks like the bleach tower is required to be at 105°F but I'm not sure of that.
You have to work in constant terms. Everything should be in mass flow rate terms. Use the density (at 55°F) of the ClO
2 and convert the flow rate to mass flow rate. Calculate the mass flow rate of the steam and add it to the pulp mass flow rate.
Then Q=mcΔT of the pulp-plus-steam stream (I'd use a mass-weighted average to get the system c
p) to find out how many BTU's you can give up to go from 155°F to 105°F. Then use the same equation on the ClO
2 to see how many BTU's are required to go from 55°F to 105°F.
This system is so constrained that I don't see how you hit your constant targets--something either the bleach flow rate or the outlet temperature need to be variable
David Simpson, PE
MuleShoe Engineering
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