Exocet
Electrical
- Feb 7, 2002
- 6
Can someone please explain the circuit operation for an Air Cleaner.
Basically on the voltage on the primary side of the transformer is 3500V and on the secondary side, one voltage rail is 9600V and the other rail is 3500V with load.
Between the 2 rails you have 2 branches of a diode and capacitor. One branch the anode of the diode is back to back with the cap and the other branch the cathode of the diode is back to back with the cap. In the first brach the node with the anode of the diode and the cap are tied to ground.
The voltage rail with the 3500V has a 226Meg ohm resistor, probably to hold the cap voltage (RC time constant).
These 2 branches are probably to rectify the alternating current and to hold the voltage.
And I believe with no load the voltage across the rails is 7500-8500V.
Just need to understand what is happening in the circuit and to better troubleshoot.
Thanks!
Basically on the voltage on the primary side of the transformer is 3500V and on the secondary side, one voltage rail is 9600V and the other rail is 3500V with load.
Between the 2 rails you have 2 branches of a diode and capacitor. One branch the anode of the diode is back to back with the cap and the other branch the cathode of the diode is back to back with the cap. In the first brach the node with the anode of the diode and the cap are tied to ground.
The voltage rail with the 3500V has a 226Meg ohm resistor, probably to hold the cap voltage (RC time constant).
These 2 branches are probably to rectify the alternating current and to hold the voltage.
And I believe with no load the voltage across the rails is 7500-8500V.
Just need to understand what is happening in the circuit and to better troubleshoot.
Thanks!