If I read the symbol at "B" correctly, the joint can develop moment and horizontal force, but no vertical. Correct? Sorry, but I have not seen this notation before.
msquared48
Mike, I also haven't seen this notation before. I just realized doing work from softwares only made me loose o basics of statics. So I started to study own my own to take the rust off. I am trying to solve this with moment area method. Can you draw out elastic curve for this or try to solve it ! !
KootenayKid
How can you change this to fixed end etc? I do not buy that
dhkahn i have great respect for you. Too many engineers forget the basis of their computer calculations and end up losing the grasp on the real core aspects on which everything else is built.
As with the beam restraint conditions i think they are both s/s roller support allowing lateral movement (no moment at this point due to it being simply supported.
Try drawing out the deflected shapes and approximates of the bending moments to see whats really happening.
lt.
As with the beam restraint conditions i think the one on the left is a s/s roller support allowing lateral movement (no moment at this point due to it being simply supported), and the other end is fixed end roller support.
Try drawing out the delfected shapes and approximates of the bending moments to see whats really happening.
Please keep us posted on your progress i shall also have a go at finding a solution
Your problem is statically determinate. You can work out the moment diagram in about 30 seconds flat. If you work out the moment diagrams for your example, and for the simplification that I suggested, you will find that they are identical. And, if the moment diagrams are identical, then so are the deflected shapes.
You could have solved this by the superposition of a couple of formulas straight out of the steel manual.
Please show me.
End A is pinned so theta A has value and matches the answer.
If I make it fixed than as per your method theta A = 0
How do you justify that?
See the sketch attached. At least I think that I've attached a sketch (I've never done it before).
I reversed the node lettering when I described the method in my intial post. You are correct of course, point A will have a rotation.
The trick to the simplification is to realise that it is only the relative displacement between ends that matters. Whether it's the pinned or guided end that does the actual travelling, is irrelevant.
KootenayKid,
Thx.
BMD is same for all these.
But elastic curve for your cantilever will not match the elsatic curve of my problem. In my problem it becomes horizontal ar support B. U can x-check with prex excel sheet above. But in typ cantilever the elsatic slope is sloping away ! !
In a flexural bending problem, if the moment diagrams are the same, the elastic curve is the same. There's just no getting around that.
Just imagine: you could also solve the problem by double integration. And, when you performed that double integration, what you'd be integrating is the moment diagram. Same moment diagram --> same deflected shape
My method results in zero slope at node B as well. How could it not, I've got that node completeley fixed??
One more thing: in a typical cantilever, the slope is most definately not sloping away from the support. It is, by definition, zero slope at the support.
Moment at point B is same (WL/2).
In your beam point B is fixed so not going anywhere.
In my problem this point rolls down and gives deflection.
See ! same BMD but different elastic curve.
