Scotty Boy
Structural
- Mar 11, 2025
- 7
Hi there,
I am currently designing a padstone to support a beam with a 77.63 kN end reaction. I am following the British Standard BS 5628-1-2005.
The BS code provides the following Figure for the design:

We see that the dispersion line illustrates the stress distribution at a 45 degree angle for a vertical distance of 0.4*h.
However, in my design, my wall is not deep enough to accommodate the full length of the 45 degree dispersion line, as shown below.

My wall is only 380 mm thick. To accommodate the full dispersion line it would need to be 1100 mm thick.
My question is, can I take the stress at the point that it marked on the diagram? Hence, (77.63 x 10^3)/(380 x 254) = 0.80 N/mm^2
Where 254 is width of the beam in mm.
Or would this be dangerous and I have to re-think the design?
I am currently designing a padstone to support a beam with a 77.63 kN end reaction. I am following the British Standard BS 5628-1-2005.
The BS code provides the following Figure for the design:

We see that the dispersion line illustrates the stress distribution at a 45 degree angle for a vertical distance of 0.4*h.
However, in my design, my wall is not deep enough to accommodate the full length of the 45 degree dispersion line, as shown below.

My wall is only 380 mm thick. To accommodate the full dispersion line it would need to be 1100 mm thick.
My question is, can I take the stress at the point that it marked on the diagram? Hence, (77.63 x 10^3)/(380 x 254) = 0.80 N/mm^2
Where 254 is width of the beam in mm.
Or would this be dangerous and I have to re-think the design?