Differential pressure measurement with PDT in cyclone reactor

[knapee]

Dear Sir

A PDT take a measurement across tap1 (EL 1500mm) and tap 2
(EL 1000mm) so that the differential pressure reading is taken across a known distance 0.5m. And the density of particle is from 400kg/m3 to 1000 kg/m3 in this reactor fluidized bed.

I wonder which formula I can used to calculated the differential pressure drop between these two tap?

Any help and comment will be appreciated.

Thank you so much.

 

[knapee]

Dear professional
I am not sure this is a silly question.
I wonder which formula in the following can be applied in this case

1. delta P=delta H?density*g

or just use

2. delta P [kg/cm2]= delta H [m] / (average density[kg/m3] / 10000)

which one is correct ?

Could any one give me a help ?

Thank you very much.

 

[danw2]

The Delta p (in units of mmH2O) measurement output = DP*specific gravity
where specific gravity is the ratio of the density of the material to the density of water.

Water's density is 1,000 Kg/m3
The material at 400Kg/m3 has an SG of 0.4
The material at 1000Kg/m3 has an SG of 1.0

If the 500mm level were at the maximum with 100% SG 1.0 material,
the DP measurement output would be DP*1.0 = 500mm

If the 500mm level were at the maximum with 100% SG 0.4 material,
the DP measurement output would be DP*0.4 = 200mm, and need correction.

The correction for actual level is DP measurement/SG.
200mm indicated output/0.4 = 500mm actual level.

I'm not clear how you will determine the 'average' SG of the blend.