Hi All, I was wondering if anyone could help me to understand the eccentricity equation in Example 1 contained in the CIRIA report C761.
The equation is Eccentricity, e2 = Md x sin(45) / Fd,
Where
Md is the moment,
Fd is the vertical force
I understand, that the eccentricity is = Md/Fd, however it is the inclusion of sin(45) that I don't quite get.
I know the question is quite specific, but If anyone has any insight on this it would be greatly appreciated!
The equation is Eccentricity, e2 = Md x sin(45) / Fd,
Where
Md is the moment,
Fd is the vertical force
I understand, that the eccentricity is = Md/Fd, however it is the inclusion of sin(45) that I don't quite get.
I know the question is quite specific, but If anyone has any insight on this it would be greatly appreciated!
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