While I am familar with that reference, I am not familar with that example.
However, I will try to explain the process the best that I can. This, of course, means that I am assuming the load you are having most difficulty with is the live load distribution.
Please keep in mind that many engineers have different methods to do this and that all may be considered accurate (likewise a few may not!).
Looking at a non-skewed bridge, and beginning with the roadway width we must determine the vehicle (actually the axle) arrangement that will produce maximum reactions at the beams(stringers/girders) that will effect the maximum load to the concrete beam cap (flexure and shear) and to the column (compression).
You can determine the number of lanes to be loaded by dividing the roadway width by 10'. Use whole number. This will give the number of vehicles to be used (one per lane).
Look at how the stringers sit atop the concrete beam. Determine which beams have to be loaded heavily in order to produce the maximum flexural, shear, compression (column) and any beam overhang responses. Assume that a stringer sits atop the concrete beam between two concrete columns. Loading this stringer will produce a maximum positive moment in the concrete beam below. So place one wheel line right atop this stringer and place the second wheel line 6' from this load. Now using simple beam distribution calculate the reaction of the second wheel line (the 6' offset) on the adjacent stringers. This will include the first wheel line that is right over the stringer and thus the reaction of that stringer should be (P+kP) where P is the wheel line load and "k" is a fraction determined by simple beam distribution. For now you can just work with P. The second or adjacent stringer to the one with the entire wheel load will also have a reaction to the remaining fraction of the wheel line inbetween the stringers, and is equal to (1-k)*P. That is for one vehicle. As you can imagine, the largest load may be produced in loading the remaining lanes. Keep in mind that the closest a wheel line can be next to another vehicle is 4' by AASHTO. Remember six feet is the distance for the axle of one vehicle.
Once you have looked at a number of load cases and are satisfied that you have all the responses completed, tabulate them according to response - Max Positive Moment, Max negative moment, Max. Compressive load etc. And you might have several load cases to look at for each. You may now multiply these "P" by the apprpropriate reaction that results from a longitudinal analysis of the spans. Usually this will result in loading the support (bent) with one axle and the other two axles are in the span at 14' increments from one another. You looking for a single wheel line reaction so this value must take into account the live load distribution (s/5.5). Also you must use the multiple lane load reduction factors which are 100% for up to two lanes loaded at one time and 90% for three lanes and 75% for four or more lanes loaded.
Once you are done with the product of the "P"s for each load case and reaction and lane reduction the sum of those for a single load case must equal the number of "P" loads originally placed for that load case. So that there is a check in this procedure.
I hope this helps. If not write and we'll discuss it some more!