Expanding on jdonville's question, is the 0.2 intended as a drained friction angle, phi', an undrained strength ratio, c/p a.k.a. Su/sigma'vc, or???
If you are looking for undrained shear strength of the soft clay, you can try Su = qc/Nc, where Nc varies from 9 to 20, depending on what test the undrained strength is referenced to, anisotropy, etc. (Nothing is simple.) Then, you get the strength ratio from Su and your estimate of sigma'vc, if that's what you want.
I've also seen Su = (qc-ut)/Nc' where Nc' is like 6 to 12.
I don't think you can get a drained friction angle from the cone in soft clay, but I'm not positive about that.
Regards,
DRG