daelo
Civil/Environmental
- Feb 7, 2013
- 2
Hello all,
First time poster here, couldn't find an introduction forum so I'll introduce myself here instead. 26 year old product designer working in the construction industry(partitions).
And here's my problem, I'm trying to design a bolted connection that uses dowel pins to provide shear strength but which also uses socket screws to withstand slip in the vertical plane. If you take a look at the attached scan you see how and see the detail of how the two blocks are clamped together with a frame which is in the middle. 2 or perhaps three socket head screws sunk into block A will screw into block B with or without helicoils if ally 6082 T6 is not suitable for the threads strength. A vertical load of 1962N or 200kg is what the clamping force will have to over come, the material between the blocks will be powder coated aluminium.
I understand that preloading of *bolts* will need to be at 75% of their proof strength,but how do you work torque into a force that can be applied to clamp the two items together without slipping. In the worst case scenario I will just settle with the dowel pins doing all the shearing work with the screws just holding the blocks in place to avoid any prying.
The dowel pin calculation has been include below, would someone mind checking? I work it out to be 2 8mm A4-80 stainless pins fitted into an m6 hole tolerance (press fit).
I've been banging my head against a brick wall all day trying to work out the clamping force equation but just cannot simply get my head around. Surely the clamping force just have to overcome a 1962N force x coefficient of friction in order for no slip to occur?
Thanks for taking the time to view my thread, and hello again!
First time poster here, couldn't find an introduction forum so I'll introduce myself here instead. 26 year old product designer working in the construction industry(partitions).
And here's my problem, I'm trying to design a bolted connection that uses dowel pins to provide shear strength but which also uses socket screws to withstand slip in the vertical plane. If you take a look at the attached scan you see how and see the detail of how the two blocks are clamped together with a frame which is in the middle. 2 or perhaps three socket head screws sunk into block A will screw into block B with or without helicoils if ally 6082 T6 is not suitable for the threads strength. A vertical load of 1962N or 200kg is what the clamping force will have to over come, the material between the blocks will be powder coated aluminium.
I understand that preloading of *bolts* will need to be at 75% of their proof strength,but how do you work torque into a force that can be applied to clamp the two items together without slipping. In the worst case scenario I will just settle with the dowel pins doing all the shearing work with the screws just holding the blocks in place to avoid any prying.
The dowel pin calculation has been include below, would someone mind checking? I work it out to be 2 8mm A4-80 stainless pins fitted into an m6 hole tolerance (press fit).
I've been banging my head against a brick wall all day trying to work out the clamping force equation but just cannot simply get my head around. Surely the clamping force just have to overcome a 1962N force x coefficient of friction in order for no slip to occur?
Thanks for taking the time to view my thread, and hello again!
