toohotforme
Mechanical
- Jan 7, 2005
- 28
Is there a source that provides detailed boiler efficiency calculations that shows how a boiler efficiency value is derived from the standpoint of the combustion side data.
This gets most confusing when the values are intermingled to suit whoever the seller is!![[mad] [mad] [mad]](/data/assets/smilies/mad.gif)
e.g. a firetube boiler fired on natural gas has CO2 of 10.5% with stack temp. of 220 degrees celcius at full load and ambient of 30C. The fuel has a higher calorific value of 40MJ/m3 and a lower calorific value of 34 MJ/kg at stp. (The stoichiometric CO2 is 11.9% and the stoichiometric air fuel ratio is 9.26)![[pc3] [pc3] [pc3]](/data/assets/smilies/pc3.gif)
We have a formula such as 100-(K * stack temp(C) - air temp(C))/CO2(%) where K = 0.54![[ponder] [ponder] [ponder]](/data/assets/smilies/ponder.gif)
so the above equation looks like this
=100-(220-30)*0.54/10.5 = 90.23% boiler efficiency.
It is apparently based on the 'Hassanstad' formula(?)![[smarty] [smarty] [smarty]](/data/assets/smilies/smarty.gif)
So,
1) where does the K factor originate? and![[party] [party] [party]](/data/assets/smilies/party.gif)
2) where does the fuel gross or net calorific value finds its way in? and![[pipe] [pipe] [pipe]](/data/assets/smilies/pipe.gif)
3) what does the efficiency mean in practice? e.g. if we burned 100kg of the above fuel of 40MJ/kg = 4GJ heat in the furnace - how much of that find its way in to the water / steam? (90.23% ? - with the balance being e.g. stack losses, radiation, latent heat of water vapour?)![[thumbsup2] [thumbsup2] [thumbsup2]](/data/assets/smilies/thumbsup2.gif)
This gets most confusing when the values are intermingled to suit whoever the seller is!
![[mad] [mad] [mad]](/data/assets/smilies/mad.gif)
e.g. a firetube boiler fired on natural gas has CO2 of 10.5% with stack temp. of 220 degrees celcius at full load and ambient of 30C. The fuel has a higher calorific value of 40MJ/m3 and a lower calorific value of 34 MJ/kg at stp. (The stoichiometric CO2 is 11.9% and the stoichiometric air fuel ratio is 9.26)
![[pc3] [pc3] [pc3]](/data/assets/smilies/pc3.gif)
We have a formula such as 100-(K * stack temp(C) - air temp(C))/CO2(%) where K = 0.54
![[ponder] [ponder] [ponder]](/data/assets/smilies/ponder.gif)
so the above equation looks like this
=100-(220-30)*0.54/10.5 = 90.23% boiler efficiency.
It is apparently based on the 'Hassanstad' formula(?)
![[smarty] [smarty] [smarty]](/data/assets/smilies/smarty.gif)
So,
1) where does the K factor originate? and
![[party] [party] [party]](/data/assets/smilies/party.gif)
2) where does the fuel gross or net calorific value finds its way in? and
![[pipe] [pipe] [pipe]](/data/assets/smilies/pipe.gif)
3) what does the efficiency mean in practice? e.g. if we burned 100kg of the above fuel of 40MJ/kg = 4GJ heat in the furnace - how much of that find its way in to the water / steam? (90.23% ? - with the balance being e.g. stack losses, radiation, latent heat of water vapour?)
![[thumbsup2] [thumbsup2] [thumbsup2]](/data/assets/smilies/thumbsup2.gif)