HSNIC
Structural
- Apr 8, 2007
- 49
I am studying up on for the April 16, 2010 Exam. I have the Civil Engineering Ref Manual 10th ed. and the 6 Minute Solutions: Geotechnical.
For a problem with the GWT between the surface and the foot base, The CERM advises to subtract 62.4 from the dry unit weight before multiplying by the quantity depth to GWT minus Depth to footing. This is to calculated the surcharge term.
((Pq+Gammadry*Dw+(Gammadry-62.4)(Df-Dw))Nq
Six minute has something similar with the dry unit weight multiplied by the Df plus 62.4 times the quantity depth to GWT minus depth to footing base.
(pq+Gammadry*Df+(62.4)(2.5-4))Nq.
The solutions use this too. I don't see using the dry unit weight to get the buoyant weight. Seems on the conservative side.
Pg 36-8 of the C.E.R.M 10th Ed. Michael Lindeburg, PE
Pg 60 Six-Minute Solutions for Civil PE Exam Geotechnical Problems. Bruce Wolle, PE.
For a problem with the GWT between the surface and the foot base, The CERM advises to subtract 62.4 from the dry unit weight before multiplying by the quantity depth to GWT minus Depth to footing. This is to calculated the surcharge term.
((Pq+Gammadry*Dw+(Gammadry-62.4)(Df-Dw))Nq
Six minute has something similar with the dry unit weight multiplied by the Df plus 62.4 times the quantity depth to GWT minus depth to footing base.
(pq+Gammadry*Df+(62.4)(2.5-4))Nq.
The solutions use this too. I don't see using the dry unit weight to get the buoyant weight. Seems on the conservative side.
Pg 36-8 of the C.E.R.M 10th Ed. Michael Lindeburg, PE
Pg 60 Six-Minute Solutions for Civil PE Exam Geotechnical Problems. Bruce Wolle, PE.