Air system through attenuators and filters confusion

[mock1]

Hi all,
I have been working on a Combined heat and Power unit that uses a CAT engine, heat recovery equipment, pumps ,etc., I have to move about 17,000 CFM through this unit and I'm at the point that I need to fit the filters and the attenuator inside the "box" that all these parts are in. Before I go into it I need to stress that I am not an engineer, I'm in training,(crash course)
I have a total pressure drop of 2" w.c. across the whole unit,my louvers are .18, filters are .39, attenuator is .32 x's 2 as there are two of them,(inlet and outlet, a frost coil that is .2" w.c. This comes to 1.41 total. My fans have a static pressure of 2".
Since my louvers and my attenuator are both 40" wide and 90" tall can my filters be the same size, (sq.ft. that is) with out changing any of my pressure drop numbers,face velocity, or CFM???

 

[ChasBean1]

I might be the only one, but I find your post a little confusing. You already have a filter pressure drop of 0.39" without having put them in yet(?) Also it's tough to tell exactly what this thing is and what its purpose in life is.

That said, 17,000 cfm through your open area gives 680 feet per minute velocity, which is higher than the upper limit for standard HVAC filters (typ. ~500 fpm). The higher velocity creates more pressure loss which could easily eat up the remaining 0.59" static the fan has left.