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  1. y061q

    Crushing large pipe with diagram

    That's great. Thanks everyone for all of the help.
  2. y061q

    Crushing large pipe with diagram

    BA, I am just running through your response and I thought: Z = (d^3 - di^3)/6 = (30"^3 - 29"^3)/6 = 435.2 "^3
  3. y061q

    Crushing large pipe with diagram

    The steel pipe would supported by a layer of 6"-8" shot rock over bedrock. This area is inter tidal so smaller bedding material can't be used
  4. y061q

    Crushing large pipe with diagram

    If I may try to simplify it (or explain it better). How would I calculate the max point load before failure of the 1/2" wall pipe that is supported at the bottom only. http://img717.imageshack.us/i/20110329074023.jpg/http://img717.imageshack.us/i/20110329074023.jpg/
  5. y061q

    Crushing large pipe with diagram

    I am having a bit of a problem. I have a 30" OD pipe (1/2" wall) on a 17 degree angle and have a 100ton weight on it. The pipe is fully supported, so I am assuming that the deflection is minimal. I can calculate the bending stress and shear but is there a way to calculate the rupture stress...

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