Hi Bill..since i´m european i´ve will rather think it over in SI units..so u writte I should multipie my el kW usage by 14 US gallons/h = more or less 53 liters/h....where do this fuel quantity comes from (we forgett all about different densities)?
..as far as i remember fuel comsuption is a...
thanks to u all by the enlightning answers---the engines in question are Wartsilla(swedish) and run on light fuel(gasoil).I observed that they share the existing load when the vessel is manoeuvring..otherwise it´s only one of them taking up most of consummers.
Actually i´m only calculating how...
..no free lunch-exactly;-)..so let´s say the el. load is for instance 1000 kWh and the specific fuel consumation is for instance 100 g/kWh..that´s will lead us to
1000* 100/1000 = 100 Kg fuel
--------that will be the relationship, i believe..please correct if i´m wrong.
,,yes..that´s what made sense to me..even though i might have expressed me otherwise,-)...it´s a fact that as refered that Energy indput= Energy ouput+losses..but nevertheless the extra electrical load will alter the torque within generator..and that will force the diesel engine to maintain...
thanks;-)...so, re-chaptering..no matter how big( in kWh) the electrical load imposed on generator is, the diesel motor fuel consumation will remain the same, right?
.....now i´m a simple mechanic studying marine engineering and I know for af fact that car generators electrical load has an...
Relationship between generator load and fuel consumation on ships auxiliary engine.
How´s this relantionship?..since the engines run on fast rpm, i still assumme that teh generator torque influences the fuel feeding,,,or not?
Thanks in advance
