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@rcwilson Yes i am macthing the voltage from avr and with potentiometer of both the generators and i also matched the phase from sycnhscope. 20 amperes that I wants is becaz its exciting current is 10 amperes rated on generator 3412 caterpillar and generators are of older models it will always...

i had checked voltages several times and matched it as they were out before.Amperes drop at 40 amperes from 53 amperes but i want it to be at 20 to 22 amperes.

starting amperes after synchrounizing are 53A to 138A at 430V to 375V amperes at no load on both generators.

Hi, i have two generators 650 kva and 420 kva wants to synchrounize both of them manually through droop and volatge gain starting amperes are 53 at 430v 50.9 hz when i synchrounize them.Plz tell me the way out.

I didnt get the reliable answer i knew that there's a way to calculate. For that there is a procedure throgh which we can easily get the exact capacity of the coil that. I didnt find it any where some peoples have knowledge about that but they didnt share with others. i have found a clue for...

I JUST WANT TO ASK THAT I HAVE A OIL BOILER MENTIONED ON ITS DOCUMENT THAT IT WILL PRODUCE 2 MILLIONS K CAL HEAT ENERGY. IT CONSISTS OF 3 TUBES OF (M.S) METAL INSIDE IT.WEISHAUPT BURNER IS USED ON THAT RATED AT 2250 KW.I WANT TO KNOW THE METHOD TO CONFORM THAT DOES IT SUPPORTS 2 MILLION K CAL...

YOU CAN ALSO CALCULATE BY 0.002893.F.LN GMD/GMR*OHMS*PHASE*KM

I HAVE A BOILER ON WHICH I USED BURNER OF WEISHAUPT 2250 KILOWATT I KNEW THAT IT IS 2 MILLION K CAL THAT MEANS 2250KW=2 MILLIONS CALLORIES BUT I WANT TO KNOW THAT HOW I CAN CALCULATE THE STRUCTURE OR TUBE SIZE ON WHCIH MY BURNER IS MOUNTED THAT IT ALSO SUPPORTS AT 2 KILO MILLION CALORIES IS...

another thing is that i have read in a book that "capacitor and inductor does not consumed real power means kilowatt actually all loads fall in these two extremes" so whats the reality of that.is it true and if it is true than how much load fall in between the capacitor and inductor.

yes you can get it through transformer 480 to 208 and it can be made on order or demand

for load of 800 kw 600 kvar but what will happen if 1100 kvar will operate

can any one explain me what will happen when i used capacitor for improving my lagging power factor during running process of induction motors capacitor operates but when machines shut down capacitor should aslo be shuted but what will happen if all capacitor will remain on even the plant is in...