Thank you Bestwrench and Unlcesyd.
Unlcesyd, it is calculating three out of four. i.e. one is broken.
Bestwrench,
Does: R = 1 – (1 – R_1)(1 – R_2)(1 – R_3)(1 – R_4). calculate the probiblity of any one of the four working? Can you reconfiure that to show three working one broken?
Tom
Hello,
I'm trying to calculate the reliability of three out of four generators working when in parallel.
Does anyone know how to do this?
Thanks in advance, Tom