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  1. huang9431

    what can I do now?Who can help me in this question?

    The FT using FFT fp=1024; % FFT Point fs=20; % Sampling frequency t=0:1/fs:2; y=sin(pi*t); Y=abs(fft(y,fp))/fp; f=fs*(0:fp/2)/fp; plot(f,Y(1:fp/2+1)); The time domain signal includes one cycle for the cycle is 2.I found that I regards w(angle frequency) as f(frequency) for mistake.The figures...
  2. huang9431

    what can I do now?Who can help me in this question?

    I found there is great difference between the result of the fourier transform using directly integration and that using FFT.What's the reason? ??The FT using FFT fp=1024; % FFT Point fs=20; % Sampling frequency t=0:1/fs:2; y=sin(pi*t); Y=abs(fft(y,fp))/fp; f=fs*(0:fp/2)/fp; plot(f,Y(1:fp/2+1))...

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