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- Users: Nabil Baig
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Bolt / Pin Design
@dvd Yes, it is supposed to be a pivot pin. Like U-hook lifts the load fixing in it. It is noy always under liad.- Nabil Baig
- Post #7
- Forum: Mechanical engineering general discussion
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Bolt / Pin Design
Hi, BriamE22, Does that mean 238/2.04 = 116.66. Is the pin 116.66 times stronger than the applied load?- Nabil Baig
- Post #4
- Forum: Mechanical engineering general discussion
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Bolt / Pin Design
Hi there, I calculated single shear stress in a pin as: Diameter of Pin = 100mm Material: IS:2062 Load / Force = 16000N so Shear Stress = Force/Area =16000N/7854mm2 =2.04 N/mm2 Shear Stress =2.04 MPa Now, Shear Strength(Yield) of IS:2062 = Tensile Strength(Yield) x...- Nabil Baig
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- Replies: 8
- Forum: Mechanical engineering general discussion
