L1 and L2 are the length and width of the plate. So depending on the orientation of the plate the Ft changes.
ie (10x0.035)=350 /0.25 = 1.4kN
That works for them all except the 2.4kN figure which is 2.333kN
Jec67 it was right though
Ft=(Si*H)/L for some reason the first result is wrong but this is probably rounding. All the rest of the results work for that.
Hi,
Could someone please help me i'm trying to understand how Ft and Fc (kN) are achieved in the attached table. The table has the other know values but I cannot seem to confirm the figures for Ft and Fc and don't wish to take them as gospel.
From the diagram I know:
Ft= Tensile Action
Fs=...
