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I am trying to work it out myself but I am at the point where I don't understand whats what and need a nudge in the right direction :/

ione, From the data sheet that you provided me with, I am lost when it comes to the Nusselt number; any help?

Bi = h*Lc/k Where: h expressed in [W/m2/K] or equivalent units is heat transfer coefficient between the fluid (water in your case) and the body (steel bar in your case). * Lc expressed in [m] or equivalent units is characteristic length of the body (generally Volume/Transverse area). k...

Right, I have Lc and k, but have been struggling for hours to work out h. Regards,

Hi all, I am having issues trying to work out a value needed to formulate the Biot number which is needed to work out what temperature a bath of water would have to be kept at to cool a specific amount of mild steel in an allotted period of time. (Quite a mouthful, I know) So far I have worked...

ione, It turns out that the amount of power/cooling required is far too much to make this viable, and you stated that "Things would be a bit different if you should have to determine the optimal water temperature for cooling purpose. The optimal temperature depends on the time available for...

Also, what is the lumped capacitance method and why may it not fully apply? Is there a specific article that I could read as I can only find rather complex formula documenting it... Regards,

LittleInch, That's very helpful thank you, the overall aim of this was to try and work out the following: Connected to the tank of water will be another reservoir that is actually cooled, and the resulting water will be pumped into the tank that the bars are dipped into, as the cooling machine...

If i use: 17kg x 0.62j/kg/k x -65 = -685.1 -685.1 / 48 seconds = -14.273 J/s or W -14.273 Js/w x 6 bars = -85.6375 watts, This seems much more realistic, but I am still unsure. Also, what is the units for the restful of the initial calculation 17kg x 0.62j/kg/k x -65 = -685.1? Regards,

Ok right, pretty sure I have got it but I need to confirm I am using the correct units so I will type it out below: (Mass of metal in 1 bar = 17kg), (Specific Heat Capacity of Mild steel = 0.62j/kg/k or 620j/kg/k SO I use 620j/kg/k as its in Kg, correct?), (Temp change (T Final - T Initial) so...

IRstuff, the 28deg C is the maximum temperature that they are allowed to be, so anywhere between say 15 and 28 would be fine. LittleInch, I have been trying but am struggling with the formula required. Regards,

Hi all, This is my first post here (hopefully of many), and there is an issue I am struggling with for my work. I am helping in designing a conveyor that takes freshly milled mild steel bars and submerges them in a tank of cooled water to reduce their temperature enough to to not damage the...