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  1. RJonTilt

    Compressor Suction Temperature

    Just one thing. It is very unlikely that the suction temperature leaving the evaporator and entering the condenser will be the same. You must take the piping losses into account.
  2. RJonTilt

    Issue with cryogenic N2 pump

    Well, here are few possible causes: 1. check the variable speed drive for a. speed ramping out of adjustment b. It may be shutting down to becasue the pump is spinning too fast, and trips the limts set in the profram. This usualy indicated that the fluid is too hot for the pump at the currnet...
  3. RJonTilt

    Exterior Dust Collection Ducts

    i am not sure what the DC means but You are most sure that the condensation is occurring if you use the following equation to determine at what temperture condensation will occur: q/A= (Tduct-Toutside)/(Rduct+R(metal+insulation) +Routside)=(Tduct-Tdp)/(Rduct) convection Resistance values are as...
  4. RJonTilt

    Ventilation of Class 1 Division 1 area

    Thw whole purpose of moving the fan out the classified area was to allow the use of the other that class I div I electrical equipment. I have install several of these. Electrical classification is based upon the concentration of the explosive gas, if you are removed from the area and the...
  5. RJonTilt

    Ventilation of Class 1 Division 1 area

    Well, that could be complicated. What is the dilution factor of the discharge? What is ther velocity of thr discharge? What will happen if the belt breaks? Do you have FM aproval to the space? Every situation has special issues. In general, if the unit has proper velocity it will dilute the...
  6. RJonTilt

    Ventilation of Class 1 Division 1 area

    If the motor is not in the air stream you are good provided the fan is spark proof. A methane system must have spark free construction.
  7. RJonTilt

    Insulation on Exterior Dust Collection Ducts

    You are most sure that the condensation is occurring if you use the following equation to determine at what temperture condensation will occur: q/A= (Tduct-Toutside)/(Rduct+Rmetal+Routside)=(Tduct-Tdp)/(Rduct) Resistance values are as follows: Rduct surface = 1/hduct so use h inside duct of 1.0...

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